To determine the frequency and energy of AM (Amplitude Modulation) and FM (Frequency Modulation) waves, we can use the relationship between wavelength (λ), frequency (f), and the speed of light (c) given by the formula:
\[ c = f \cdot \lambda \]
where:
- \( c \) is the speed of light (approximately \( 3 \times 10^8 \) meters per second),
- \( f \) is the frequency,
- \( \lambda \) is the wavelength.
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For AM waves (wavelength ≈ 100 meters): \[ f = \frac{c}{\lambda} = \frac{3 \times 10^8 \text{ m/s}}{100 \text{ m}} = 3 \times 10^6 \text{ Hz} \text{ or } 3 \text{ MHz} \]
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For FM waves (wavelength ≈ 1 meter): \[ f = \frac{c}{\lambda} = \frac{3 \times 10^8 \text{ m/s}}{1 \text{ m}} = 3 \times 10^8 \text{ Hz} \text{ or } 300 \text{ MHz} \]
From the calculations, we find that FM waves have a higher frequency than AM waves.
Next, regarding energy, the energy of a photon is related to its frequency by the equation: \[ E = h \cdot f \] where:
- \( E \) is the energy,
- \( h \) is Planck's constant (approximately \( 6.626 \times 10^{-34} \) J·s),
- \( f \) is the frequency.
Since FM waves have a higher frequency than AM waves, they will also have higher energy.
Conclusion:
- FM has a higher frequency and higher energy.
Thus, the correct response is: FM has a higher frequency and higher energy.
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