To determine which wave (AM or FM) has a higher frequency and energy, we can use the relationship between wavelength (λ), frequency (f), and the speed of light (c), which is given by the equation:
\[ c = f \times λ \]
Given that the speed of light (c) is approximately \(3 \times 10^8\) meters per second:
-
For AM waves with a wavelength of approximately 100 meters: \[ f_{AM} = \frac{c}{λ_{AM}} = \frac{3 \times 10^8 \ \text{m/s}}{100 \ \text{m}} = 3 \times 10^6 \ \text{Hz} \ (or \ 3 \ \text{MHz}) \]
-
For FM waves with a wavelength of approximately 1 meter: \[ f_{FM} = \frac{c}{λ_{FM}} = \frac{3 \times 10^8 \ \text{m/s}}{1 \ \text{m}} = 3 \times 10^8 \ \text{Hz} \ (or \ 300 \ \text{MHz}) \]
From the calculations:
-
The frequency of FM waves (300 MHz) is significantly higher than that of AM waves (3 MHz).
-
Energy of a wave is directly related to its frequency, as described by the equation \(E = h \times f\) (where \(E\) is energy, \(h\) is Planck's constant, and \(f\) is frequency).
Since FM waves have a higher frequency, they also have higher energy.
Conclusion:
FM has a higher frequency and higher energy.
Thus, the correct response is:
FM has a higher frequency and higher energy.
3 answers