area of loop = .02^2 = .0004 m^2
dB/dt = .044/.1 = .44
emf = A dB/dt = .0004 *.44 = 1.76 * 10^-4 = .00018 V
Am i Correct?
2.0 cm*.044T*/.10 s= 0.88 V
Each side of a square loop of wire measures 2.0 cm. A magnetic field of 0.044 T perpendicular to the loop changes to zero in 0.10 s. What average emf is induced in the coil during this change?
A. 1.8 V
B. 0.088 V
C. 0.88 V <--
D. 0.00018 V
1 answer
1 answer