Anything times 1 or to the first power is itself. Unless you have typos, here is what I get:
(2x)^3 + 12x^2 * (-5y) + 6x * 25y^2 - 125y^3 =
8x^3 - 60x^2y + 150xy^2 - 125y^3
am i correct?
1(2x)^3 + 3(2x)^2*(-5y)^1 + 3(2x)^1*(-5y)^2 + 1(-5y)^3
answer
(2x-5y)^3
3 answers
luckily, the answers agree!
Ok,thank you guys! :)