Alvin, Calvin and Melvin each have some positive integer number of sweets. Alvin has fewer sweets than Calvin, and they have 27 sweets in total. Melvin has 19 sweets more than Alvin.

Question

What is the maximum number of sweets that they can all have in total?

Answer 1

A < C
A + C = 27
M = A + 19
Note that from the third relationship, to maximize M, we also have to maximize A.
From the second relationship, we want A to be maximize in a way that it is still less than C. Thus the maximum possible integer for A = 13, so that C = 14. Thus,
M = 13 + 19
M = 32
Knowing all the values, we get their sum:
13 + 14 + 32 = 59

Hope this helps~ :3

Answer 2

OI U WASTE ITS WOTNG oh muneeb SILENCE I KILL YOU!