The balanced chemical equation for the decomposition of aluminum oxide is:
2 Al2O3 → 4 Al + 3 O2
From the equation, we can see that for every 4 moles of aluminum (Al) produced, we have 3 moles of oxygen gas (O2) produced.
Therefore, the ratio of aluminum to oxygen gas in the products of the reaction is 4:3.
Aluminum oxide, Al2O3, decomposes into aluminum, Al, and oxygen gas, O2. Which ratio of aluminum to oxygen gas is in the products of the reaction?
4:3
3:2
1:3
2:3
1 answer
1 answer