To find the volume of an aluminum block given its mass and density, you can use the formula:
\[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} \]
First, convert the mass from kilograms to grams, since the density is given in grams per milliliter:
\[ 55.67 \text{ kg} = 55,670 \text{ g} \]
Now, using the density of aluminum, which is 2.70 g/mL, we can calculate the volume:
\[ \text{Volume} = \frac{55,670 \text{ g}}{2.70 \text{ g/mL}} \approx 20,594.44 \text{ mL} \]
So, the volume of the aluminum block is approximately 20,594.44 mL.
If you need the volume in liters, you can convert milliliters to liters (1 mL = 0.001 L):
\[ 20,594.44 \text{ mL} = 20.59444 \text{ L} \approx 20.59 \text{ L} \]
Therefore, the volume of the aluminum block is approximately 20.59 L or 20,594.44 mL.