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Aluminum and Oxygen form an ionic compound. Determine which is true:

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0 points
True False
Aluminum has a charge of +3.
Aluminum has 4 valence electrons.
Oxygen has 6 valence electrons.
The formula for Alumnimum & Oxygen is Al₃O₂.
The formula for Alumnimum & Oxygen is Al₂O₃.
Aluminum has a charge of +3.
Aluminum has 4 valence electrons.
Oxygen has 6 valence electrons.
The formula for Alumnimum & Oxygen is Al₃O₂.
The formula for Alumnimum & Oxygen is Al₂O₃.

1 answer

Let’s evaluate each statement regarding aluminum (Al) and oxygen (O) and their ionic compounds:

  1. Aluminum has a charge of +3. True: Aluminum typically loses three electrons to form a +3 charge in ionic compounds.

  2. Aluminum has 4 valence electrons. False: Aluminum has 3 valence electrons (it is in Group 13 of the periodic table).

  3. Oxygen has 6 valence electrons. True: Oxygen has 6 valence electrons (it is in Group 16 of the periodic table).

  4. The formula for Aluminum & Oxygen is Al₃O₂. False: This is incorrect.

  5. The formula for Aluminum & Oxygen is Al₂O₃. True: The correct formula is Al₂O₃; two aluminum atoms combine with three oxygen atoms to balance the charges (+6 from 2 Al and -6 from 3 O).

Summary:

  • Aluminum has a charge of +3: True
  • Aluminum has 4 valence electrons: False
  • Oxygen has 6 valence electrons: True
  • The formula for Aluminum & Oxygen is Al₃O₂: False
  • The formula for Aluminum & Oxygen is Al₂O₃: True

So, the correct statements are:

  1. True
  2. False
  3. True
  4. False
  5. True