Let’s evaluate each statement regarding aluminum (Al) and oxygen (O) and their ionic compounds:
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Aluminum has a charge of +3. True: Aluminum typically loses three electrons to form a +3 charge in ionic compounds.
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Aluminum has 4 valence electrons. False: Aluminum has 3 valence electrons (it is in Group 13 of the periodic table).
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Oxygen has 6 valence electrons. True: Oxygen has 6 valence electrons (it is in Group 16 of the periodic table).
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The formula for Aluminum & Oxygen is Al₃O₂. False: This is incorrect.
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The formula for Aluminum & Oxygen is Al₂O₃. True: The correct formula is Al₂O₃; two aluminum atoms combine with three oxygen atoms to balance the charges (+6 from 2 Al and -6 from 3 O).
Summary:
- Aluminum has a charge of +3: True
- Aluminum has 4 valence electrons: False
- Oxygen has 6 valence electrons: True
- The formula for Aluminum & Oxygen is Al₃O₂: False
- The formula for Aluminum & Oxygen is Al₂O₃: True
So, the correct statements are:
- True
- False
- True
- False
- True