Al ==> Al^+ + 3e Eo ox = ?
Ag^+ + e ==> Ag Eo red = 0.8
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Al + 3Ag^+ ==> 3 Ag + Al^3+ E=2.46
? + 0.8 = 2.46
? in this set up is the oxidation potential. Change the sign to make it the reduction potential.
'Aluminium displaces hydrogen from dilute HCl whereas silver does not. The E.M.F. of a cell prepared by combining Al /Al 3 andAg/Ag is 2.46 V. The reduction potential of silver electrode is 0.80 V. The reduction potential of aluminium electrode is :
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