Altitudes in Right Triangles Quick Check 5 of 55 of 5 Items Question Use the image to answer the question. Use the geometric mean to find the value of x, which is the shortest leg of the large triangle. Round to the nearest tenth, if necessary. (1 point) Responses 15 15 8 8 4.9 4.9 2.8 2.8 Skip to navigation page 15 of 15 Formula keypad has been closed. Press Control + Backslash to open it again.Formula keypad has been closed. Press Control + Backslash to open it again.Formula keypad has been closed. Press Control + Backslash to open it again.Formula keypad has been closed. Press Control + Backslash to open it again.Formula keypad has been closed. Press Control + Backslash to open it again.

1 answer

To calculate the value of \( x \) (the shortest leg of the large triangle) using the geometric mean, we need to use information typically derived from right triangles and their altitudes. The geometric mean is often applied in relation to the legs of a right triangle and the altitude drawn to the hypotenuse.

The formula that often comes into play is:

\[ x^2 = \frac{a \cdot b}{c} \]

where:

  • \( a \) and \( b \) are the lengths of the segments of the hypotenuse formed by the altitude,
  • \( c \) is the length of the hypotenuse.

Without the specific lengths from the triangle in the image you referenced, I cannot provide a specific answer.

Typically, you would follow these steps:

  1. Identify the lengths of segments \( a \) and \( b \).
  2. Calculate the length \( c \) of the hypotenuse.
  3. Substitute these values into the geometric mean formula.
  4. Solve for \( x \).

Please provide the values for the segments and the hypotenuse or describe the image to help further.

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