To find the total time for all three games, we need to add up the individual game times. The first game lasted half hour, which can be represented as 1/2 hour. The second game lasted 1/5 hour, and the third game lasted 1 2/3 hours, which can be converted to 1 + 2/3 = 3/3 + 2/3 = 5/3 hours.
Adding up the game times, we get 1/2 + 1/5 + 5/3 = (15 + 6 + 25)/30 = 46/30
The fraction can be simplified further by dividing the numerator and denominator by their greatest common divisor, which is 2.
Thus, 46/30 can be simplified to 23/15.
Therefore, Peter took 23/15 hours to defeat Connor in all three games.
Although playing chess doesn't intrigue
Connor, he agreed to play a few games with Peter. Peter has a real knack for the game and easily defeated Connor every time they played. The first game lasted half of an hour. The second game took one-fifth of an hour and the third game was over in one and two-thirds hours. How long did it take Peter to defeat Connor all three times?
1 answer
1 answer