Asked by Jacy
Alright, here is my question:
22. References list the Ka value of hydrosulphuric acid, H 2S(aq) , as
1.1 x 10^–7 at 25°C. Assume a solution is prepared by dissolving 1.00 g of H2S(g) to make 1.00 L of acidic solution. What percentage of this solution will ionize?
And I don't know how to find the percent which would ionize, but I have figured out this information:
Concentration is equal to 0.029334mol/L
[H+] is equal to 5.68x10^-5
Can you help me on this question, thanks!
I concur with 0.0293 M H2S as well as (H^+)=5.68 x 10^-5 M.
So %ionized = [(amt ionized)/0.0293]x100 = (5.68 x 10^-5/0.0293)x 100 = ??
I prefer to call 1.1 x 10^-7 k1 and not Ka. I hope this helps. %ionization is nothing more than the fractional part of the initial amount that ended up as ions (then converted to percent by multiplying by 100).
22. References list the Ka value of hydrosulphuric acid, H 2S(aq) , as
1.1 x 10^–7 at 25°C. Assume a solution is prepared by dissolving 1.00 g of H2S(g) to make 1.00 L of acidic solution. What percentage of this solution will ionize?
And I don't know how to find the percent which would ionize, but I have figured out this information:
Concentration is equal to 0.029334mol/L
[H+] is equal to 5.68x10^-5
Can you help me on this question, thanks!
I concur with 0.0293 M H2S as well as (H^+)=5.68 x 10^-5 M.
So %ionized = [(amt ionized)/0.0293]x100 = (5.68 x 10^-5/0.0293)x 100 = ??
I prefer to call 1.1 x 10^-7 k1 and not Ka. I hope this helps. %ionization is nothing more than the fractional part of the initial amount that ended up as ions (then converted to percent by multiplying by 100).
Answers
There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.