Allegra's favorite ride at the Barrel-O-Fun Amusement Park is the Flying Umbrella, which is lifted by a hydraulic jack. The operator activates the ride by applying a forcce of 72 N to a 3.0-cm-wide cylindrical piston, which holds the 20000. N ride off the ground. What is the diameter of the piston that holds the ride?
5 answers
Is it 32.57 cm?
pressure1=pressure2
force1/area1=force2/area2
force1/diam1^2=force2/diam2^2
diameter2= sqrt(force2/force1) * diameter1
= sqrt (20,000/72)* 3cm
= a little over 60cm
force1/area1=force2/area2
force1/diam1^2=force2/diam2^2
diameter2= sqrt(force2/force1) * diameter1
= sqrt (20,000/72)* 3cm
= a little over 60cm
thanx!!
When I solve this problem, I get 32.58.
I am pretty sure you got the answer correct - not BOBPURSELY.
I am pretty sure you got the answer correct - not BOBPURSELY.
HERE IS THE CORRECT WORK:
pressure1 = pressure2
force1/area1 = force2/area2
72/3 = 20,000/x
24x = 20,000
x(area) = 833.3333333333
we have the area, but the question asks for the diameter.
area = PI * r^2
833.3 = PI * r^2
r = 16.29 cm
diameter = 2r
16.29 * 2 = __32.58176 cm__
pressure1 = pressure2
force1/area1 = force2/area2
72/3 = 20,000/x
24x = 20,000
x(area) = 833.3333333333
we have the area, but the question asks for the diameter.
area = PI * r^2
833.3 = PI * r^2
r = 16.29 cm
diameter = 2r
16.29 * 2 = __32.58176 cm__
0 answers