by the way
thats 2a^2 squared
and a^2 squared. Thanks.
All of these are different problems. Please help me. IF you only know one answer to just one problem, that is totally welcome as well. THank you.
5 > |x | + 1
2a2-32
a2 + 4a + 21
7 answers
Your last two mathematical expressions are not equations, so there is nothing to solve.
Did you mean to write
a^2 + 4a = 21
for the last problem? If so, use the fact that
a^2 + 4a -21 = (a + 7)(a - 3)
Perhaps you also meant to write
2a^2 = 32
If so, divide both sides of the equation by 2 and take the square roots of both sides.
The problem
5 > |x| + 1
can be rewritten
4 > |x|
which requires that -4 < x < 4
Did you mean to write
a^2 + 4a = 21
for the last problem? If so, use the fact that
a^2 + 4a -21 = (a + 7)(a - 3)
Perhaps you also meant to write
2a^2 = 32
If so, divide both sides of the equation by 2 and take the square roots of both sides.
The problem
5 > |x| + 1
can be rewritten
4 > |x|
which requires that -4 < x < 4
yeS I did mean to write it the way you put it. Thank you.
For the second problem,
if I do this
2a^2=32
/2
a^2=16
/^2
a=4?
For the second problem,
if I do this
2a^2=32
/2
a^2=16
/^2
a=4?
a=sqrt 16 or +or- 4
Wait actually I meant to put
a^2+4a+21 would the answer be
a+7 a+3?
a^2+4a+21 would the answer be
a+7 a+3?
Also, if someone is still avalibe the problem is asking me to factor
2a^2-32
2a^2-32
2(a^2-16) but a^2-16 is the difference of two squares so
2 (a-4) (a+4)
2 (a-4) (a+4)
0 answers