Asked by b

Aljhumar is trying to arrange his room. He pushes an 80kg cabinet across the wooden room which resists the motion with a 300N force of friction. What is the coefficient of sliding friction between the cabinet and the floor?
Answered by Henry
M*g = 80 * 9.8 = 784 N. = Wt. of cabinet = Normal force(Fn).

Fk = u*Fn. 300 = u*784, u = ?.
There are no AI answers yet. The ability to request AI answers is coming soon!