Let \( x \) be the number of pounds of apples Alisha sold, and \( y \) be the number of pounds of bananas sold.
From the problem, we have the following equations based on the information provided:
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The total weight of the fruits sold: \[ x + y = 200 \]
-
The total revenue from selling the fruits: \[ 2x + 3y = 480 \]
We can solve these equations step by step.
First, we can express \( y \) from the first equation: \[ y = 200 - x \]
Now substitute this expression for \( y \) into the second equation: \[ 2x + 3(200 - x) = 480 \]
Expanding this, we get: \[ 2x + 600 - 3x = 480 \]
Combining the \( x \) terms gives us: \[ -1x + 600 = 480 \]
Subtracting 600 from both sides results in: \[ -x = 480 - 600 \] \[ -x = -120 \]
Multiplying both sides by -1 gives: \[ x = 120 \]
Now, we substitute \( x = 120 \) back into the equation for \( y \): \[ y = 200 - 120 = 80 \]
Thus, Alisha sold:
- 120 pounds of apples
- 80 pounds of bananas
To confirm, let's check the revenue:
- Revenue from apples: \( 2 \cdot 120 = 240 \)
- Revenue from bananas: \( 3 \cdot 80 = 240 \)
- Total revenue: \( 240 + 240 = 480 \), which matches the given total.
Therefore, the number of pounds of apples Alisha sold is: \[ \boxed{120} \]