Algebraically, determine the vertex form of a quadratic relation, if the vertex is at (-1, 2) and the point (1, -10) is on the parabola. Show all of your steps.

I know that the formula is y=a(x-h)suared+ k but how do i apply these numbers to this formula?

Thank you!

1 answer

given the vertex, you know that

y-2 = a(x+1)^2
Since (1,-10) is on the graph,

-10-2 = a(1+1)^2
-12 = 4a
a = -3

y-2 = 3(x+1)^2
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