Algebraic Expressions Portfolio Worksheet
Question 1
a.
The cost of one ticket is $2. The amusement tax is 15% of the ticket price. Thus, the total cost \( C \) in terms of \( t \) (the price of a ticket) can be represented as:
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Total Cost including tax: \[ C_1 = t + 0.15t = 1.15t \]
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Total Cost represented in terms of the ticket price, considering two factors: \[ C_2 = 2 + 0.15 \times 2 = 2 + 0.30 = 2.30 \]
b.
Choose \( t = 12.50 \): Using \( C_1 = 1.15t \): \[ C = 1.15 \times 12.50 = 14.375 \] Rounded to the nearest penny, the total cost is: \[ C \approx 14.38 \]
c.
We need to solve the expression \( 1.15t \) with \( 17.50 < C < 20 \): \[ 17.50 < 1.15t < 20 \] Dividing all parts by 1.15: \[ \frac{17.50}{1.15} < t < \frac{20}{1.15} \] Calculating: \[ 15.217 < t < 17.391 \] Thus, a possible value for \( t \) could be \( t = 16.00 \).
Question 2
a.
For the power tools with \( d \):
- Total cost with discount: \[ C_1 = d - 0.15d = 0.85d \]
- Total paid: \[ C_2 = d - 0.15d = 0.85d \]
Since we need total payments with respect to discount, both expressions simplify to the same total cost formula.
b.
The expression \( 0.90(d - 5) \) refers to the total paid for a piece of jewelry after applying a 10% discount to the cost after subtracting 5 dollars from \( d \). It can also be expressed as: \[ 0.90d - 4.5 \]
c.
Choose \( d = 30 \):
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Power tools: \[ 0.85d = 0.85 \times 30 = 25.50 \]
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Water Skis: \[ C_W = (d + 15) \times (1 - 0.25) = (30 + 15)(0.75) = 45(0.75) = 33.75 \]
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Jewelry: \[ (d - 5) \times 0.90 = (30 - 5)(0.90) = 25(0.90) = 22.50 \]
Final costs:
- Power tools: $25.50
- Water skis: $33.75
- Jewelry: $22.50
Winona and Takoda should buy the power tools because they offer the best value with a total cost of $25.50, making it a great gift option for their mother.
Question 3
a.
Let’s choose Pleasantville, where \( x \) represents the population:
- Current population: \[ P_1 = x - 0.02x = 0.98x \]
- In terms of growth: \[ P_2 = x \times (1 - 0.02) = 0.98x \]
b.
For Concord, let \( p \) be its population and I will choose a negative change of -3%:
- Current estimated population: \[ P_C_1 = p - 0.03p = 0.97p \] \[ P_C_2 = p \times (1 - 0.03) = 0.97p \]
c.
Choose \( p = 7000 \): Using \( P_C = 0.97p \): \[ P_C = 0.97 \times 7000 = 6790 \] Thus, the estimated current population of Concord is approximately 6790. I used this expression as it represents a direct calculation of the population decrease at the specified percentage change.
Question 4
a.
The perimeter \( P \) of A’Leila's rectangular pen can be given by:
- Perimeter: \[ P_1 = 2a + 2b \]
- Simplified perimeter: \[ P_2 = 2(a + b) \]
b.
Choose \( a = 10 \): Using \( P_1 = 2a + 2b \): \[ P = 2(10) + 2b = 20 + 2b \] The value of \( b \) was not defined in the instructions; let's assume \( b = 5 \): \[ P = 20 + 10 = 30 \]
c.
I used this expression because it fully accounts for both lengths of the pen sides combined to find the overall total perimeter. Adjusting for \( b \) allows greater flexibility in outcome calculations depending on chosen side lengths.
This completed portfolio reflects the calculations and logic behind the algebraic expression problems as directed in the instructions.