Asked by Robert
Algebra Question: A team wins 15 of their first 20 games. If they win only half the time from now on, how many games will they have to play in order to win 60% of their total games? I have it figured out manually, but cant get it in equation form.
Answers
Answered by
Reiny
total number of games ---- x
played so far ---- 20
to be played --- x-20
(15 + (x-20)/2 )/x = 6/10
15 + x/2 - 10 = (6/10)x
times 10
150 + 5x - 100 = 6x
x = 50
So they still have to play 30 games and win 15 of those.
check:
Having won 15 so far, and still hoping to win 15 more, ....
30/50 = 6/10 = 60%
played so far ---- 20
to be played --- x-20
(15 + (x-20)/2 )/x = 6/10
15 + x/2 - 10 = (6/10)x
times 10
150 + 5x - 100 = 6x
x = 50
So they still have to play 30 games and win 15 of those.
check:
Having won 15 so far, and still hoping to win 15 more, ....
30/50 = 6/10 = 60%
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