Algebra 2A Semester Exam

Question

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Question
Solve the radical equation 3x2−10−−−−−−√5+7=4
to find the two solutions.(1 point)

Answer 1

To solve the radical equation \( \sqrt{3x^2 - 10} + 7 = 4 \), we can follow these steps:

1. Isolate the radical: \[ \sqrt{3x^2 - 10} = 4 - 7 \] \[ \sqrt{3x^2 - 10} = -3 \]

2. Since the square root of a real number cannot be negative, we conclude that there are no real solutions for this equation.

Thus, the equation \( \sqrt{3x^2 - 10} + 7 = 4 \) has no solutions.

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