Alex is planning to surround his pool ABCD with a single line of tiles. How many units of tile will he need to surround his pool? Side AB measures 2.24 units. Diagonal BD measures 5 units. Round your answer to the nearest hundredth.

A coordinate plane with quadrilateral ABCD at A 0 comma 3, B 2 comma 4, C 4 comma 0, and D 2 comma negative 1. Angles A and C are right angles, the length of segment AB is 2 and 24 hundredths units, and the length of diagonal BD is 5 units.

8.96
10.48
13.42
20.42

1 answer

To find the number of units of tile Alex will need to surround his pool, we need to calculate the perimeter of the quadrilateral ABCD.

First, we find the lengths of all sides:

  1. Length of AB: Given as 2.24 units.

  2. Length of BC: To find this side, we'll calculate the distance between points B (2, 4) and C (4, 0).

Using the distance formula: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] we have: \[ d = \sqrt{(4 - 2)^2 + (0 - 4)^2} = \sqrt{(2)^2 + (-4)^2} = \sqrt{4 + 16} = \sqrt{20} = 2\sqrt{5} \approx 4.47 \text{ units} \]

  1. Length of CD: To find this length, we calculate the distance between C (4, 0) and D (2, -1). \[ d = \sqrt{(2 - 4)^2 + (-1 - 0)^2} = \sqrt{(-2)^2 + (-1)^2} = \sqrt{4 + 1} = \sqrt{5} \approx 2.24 \text{ units} \]

  2. Length of DA: To find this length, we calculate the distance between D (2, -1) and A (0, 3). \[ d = \sqrt{(0 - 2)^2 + (3 - (-1))^2} = \sqrt{(-2)^2 + (4)^2} = \sqrt{4 + 16} = \sqrt{20} = 2\sqrt{5} \approx 4.47 \text{ units} \]

Now we can calculate the total perimeter \(P\) of quadrilateral ABCD:

\[ P = AB + BC + CD + DA \] \[ P = 2.24 + 4.47 + 2.24 + 4.47 \] \[ P = 2.24 + 2.24 + 4.47 + 4.47 = 4.48 + 8.94 = 13.42 \text{ units} \]

The total length of tile needed to surround his pool is approximately 13.42 units.

Rounding to the nearest hundredth, the answer is: \[ \boxed{13.42} \]