y=mx+b
slope is the rate of change and whenever something says per it is a rate. Meaning m=13 and then he already will gain $50 just for accepting. Y-intercept is the initial value, so b=50. t or x is the hours worked=7.
c=30(t)+50 (for any # of hours)
c=30(7)+50 c=260
Alex has been offered $50 to accept the job, plus, $13 per hour. Alex claims he will complete the job in 7 hours. How would you write this as a linear equation in the form of:
c = mt + b
if c is the cost and t is the time, m is the slope, and b is the y-intercept.
Please help!!
2 answers
Well, let's consider each piece we're given:
$50 as a down payment for accepting the job -> This value doesn't change regardless of how many Alex would work on the job. He would get the money ahead of time, meaning that the value is constant and would fit perfectly as our y-intercept.
$13 per hour -> the "per hour" should stand out to you because the amount of money he gets is directly dependent upon how many hours he puts into the job. Say, he worked two hours, he'd make $(13 x 2) for that day. The "per hour" lets us know that we need a variable in place of that for our linear equation ($13 itself doesn't change however, it only changes when it's been affected by some other value, time.)
$50 as a down payment for accepting the job -> This value doesn't change regardless of how many Alex would work on the job. He would get the money ahead of time, meaning that the value is constant and would fit perfectly as our y-intercept.
$13 per hour -> the "per hour" should stand out to you because the amount of money he gets is directly dependent upon how many hours he puts into the job. Say, he worked two hours, he'd make $(13 x 2) for that day. The "per hour" lets us know that we need a variable in place of that for our linear equation ($13 itself doesn't change however, it only changes when it's been affected by some other value, time.)
1 answer