To solve for the surface area of the right circular cylinder, we need to find the lateral surface area and the area of the two circular bases.
Lateral Surface Area = 2πrh
Lateral Surface Area = 2 * 3.14 * 15.5 * 28
Lateral Surface Area = 2 * 3.14 * 434
Lateral Surface Area = 6.28 * 434
Lateral Surface Area = 2,725.52 cm²
Circular Base Area = πr²
Circular Base Area = 3.14 * (15.5/2)²
Circular Base Area = 3.14 * 7.75²
Circular Base Area = 3.14 * 60.06
Circular Base Area = 188.58 cm²
Total Surface Area = Lateral Surface Area + 2 * Circular Base Area
Total Surface Area = 2,725.52 + 2 * 188.58
Total Surface Area = 2,725.52 + 377.16
Total Surface Area = 3,102.68 cm²
Therefore, the surface area of the right circular cylinder is approximately 3,102.68 cm². The closest answer choice is 1,508.77 cm².
Aleksandr has a roll of paper that is in the shape of a right circular cylinder. It has a height of 28 cm and a diameter of 15.5 cm. Help Aleksandr solve for the surface area. Use 3.14 for π .(1 point)
Responses
1,362.76 cm2
1,362.76 cm squared
4,234.29 cm2
4,234.29 cm squared
1,508.77 cm2
1,508.77 cm squared
1,739.95 cm2
1 answer