Alcohol flows smoothly through a horizontal pipe that tapers in cross-sectional area from A1 = 41.9 cm2 to A2= A1/3. The pressure difference Äp between the wide and the narrow sections of the pipe is 11.1 kPa. What is the volume flow rate ÄV/Ät of the alcohol? The density of the alcohol is ñ = 838 kg/m3. Hint: Treat as an ideal fluid. You will need both the conservation of mass properties and the conservation of energy properties.
i currently have..
V1=[V2(0.1397m^2)]/(o.419m^2)
not sure how to apply the conservation of energy properties..any help is greatly appreciated.
2 answers
I would use bernoulli's equation.
Sub v1 into bernoulli's law and solve for v2.
A2v2 = volume rate flow
A2 = 1/3 A1
(Do not worry about (-)ve sign
A2v2 = volume rate flow
A2 = 1/3 A1
(Do not worry about (-)ve sign
0 answers