To balance the equation \( 2 \text{Ag}_2\text{O} \rightarrow \).
- On the reactant side, you have 2 moles of \( \text{Ag}_2\text{O} \), which breaks down into 4 moles of silver (Ag) and 2 moles of oxygen (O).
- To balance the products, you need 4 moles of silver and 1 mole of \( \text{O}_2 \) (which contains 2 moles of oxygen).
So, the balanced equation looks like this:
\[ 2 \text{Ag}_2\text{O} \rightarrow 4 \text{Ag} + \text{O}_2 \]
You can drag the responses into the correct areas as follows:
- In the first response area, place "4Ag"
- In the second response area, place "O2"
So your completed input will be:
\[ 2 \text{Ag}_2\text{O} \rightarrow \text{(4Ag)} + \text{(O}_2\text{)} \]