as written, 6 moles of NO produce 5 moles of N2
(The equation doesn't balance, but I assume there are other products involved - ?)
mass of N2 = 28
145g NO = 145/28 = 5.18 moles
5.18mN2 * 6mNO/5mN2 = 6.21mNO
mass of NO = 30
6.21m * 30g/m = 186g
Al2O3(s)+6NO(g)---->5N2(g)+6H2O(l)
how many grams of Nitric Oxide are required to produce 145g of nitrogen in the following reaction?
1 answer