Air trapped in a cylinder fitted with a piston occupies 162.2 mL at 1.08 atm pressure. What is the new volume when the piston is depressed, increasing the pressure by 25%?

Answer 1

assuming a constant temperature,

PV = kT is constant.

So, with 5/4 the pressure, you get 4/5 the volume

Answer 2

i dont understand

Answer 3

You can do also by using
P1V1 = P2V2
P1 = 1.08 atm and P2 = 1.08+0.25*1.08 = ?
V1 is given. Solve for V2

Answer 4

is it 1.23?

Answer 5

116.56 ml