Again, from my previous question about gravimetric analysis...

Why can't NH4Cl be used as a substitute for NH3 in precipitating MgNH4PO4*6H2O?
Please critique my thought:
I found out that a precipitate is more soluble at lower pH and since NH4Cl acidic, it will cause the precipitate to revert to its dispersed state and may cause loss of analyte. Am I right?

Yes.

thanks a lot :D

1 answer

You're welcome!

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