Again consider the model propeller of the previous problem. If we assume the jet velocity to be equal to the velocity of the air through the propeller, then we can say that , where is the air density, is the propeller area and is the speed of the flow through the propeller.

Given that the test was performed with an air density of 1.225 kilograms per cubic metre, determine the propeller diameter (in metres

1 answer

To determine the propeller diameter given the relationship between jet velocity, air density, propeller area, and flow speed through the propeller, we need to use the formula for the area of a circle, as well as the relationship given.

The equation you mentioned can be interpreted as:

\[ Q = A \cdot V \]

Where:

  • \( Q \) is the flow rate through the propeller,
  • \( A \) is the area of the propeller,
  • \( V \) is the velocity of the air through the propeller.

The area \( A \) of a circular propeller is given by:

\[ A = \pi \left( \frac{d}{2} \right)^2 = \frac{\pi d^2}{4} \]

Where \( d \) is the diameter of the propeller.

From your statement, if we assume that the jet velocity is equal to the velocity of air through the propeller, we need to rearrange and express \( d \) in terms of \( Q \), the air density \( \rho \), and the velocity \( V \).

  1. We know \( Q \) (flow rate) can also be expressed in terms of air density and velocity:

\[ Q = \rho A V \]

Equating the two flow rate expressions yields:

\[ A \cdot V = \rho A V \]

This suggests that we already have a consistent relationship; we need to establish a specific quantity related to the flow rate, which isn't provided. Let's assume we are provided with flow rate \( Q \) or the velocity \( V \).

  1. If further data (e.g., a specific velocity of flow through the propeller or flow rate) was given, we could plug those into the equations to find the diameter.

However, without specific values for flow rate \( Q \) or velocity \( V \), and assuming we still want a general solution, we can rearrange to find \( d \).

  1. Solving for diameter \( d \):

Assuming a given velocity \( V \), the area can be derived as:

\[ A = \frac{Q}{V} \]

And substituting this into the area formula:

\[ \frac{\pi d^2}{4} = \frac{Q}{V} \]

Rearranging gives us:

\[ d^2 = \frac{4Q}{\pi V} \] \[ d = \sqrt{\frac{4Q}{\pi V}} \]

Given the air density is \( 1.225 , \text{kg/m}^3 \), if you provide values for \( V \) and \( Q \), you can substitute that in to calculate the specific diameter \( d \).

Without these specific values, we can only express the diameter \( d \) in terms of \( Q \) and \( V \):

  • Provide further details about \( Q \) or \( V \) and potentially calculate \( d \).