To find the volume of water in container B, we first need to calculate the volumes of both containers A and B.
Volume of container A:
V(A) = πr^2h
V(A) = π(4)^2(16)
V(A) = 256π ≈ 804.25 cubic feet
Volume of container B:
V(B) = πr^2h
V(B) = π(6)^2(11)
V(B) = 396π ≈ 1243.71 cubic feet
After the pumping is complete, the volume of water in container B is the difference between the volume of container B and the volume that was transferred to container A, which is 804.25 cubic feet.
Volume of water in container B = 1243.71 - 804.25
Volume of water in container B ≈ 439.46 cubic feet
Therefore, the volume of water in container B, to the nearest tenth of a cubic foot, is 439.5 cubic feet.
After the pumping us complete, what is the volume of water in container B, to the nearest tenth of a cubic foot? Container A r=4 h=16. Container B r=6 h=11
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