After selling 14 1/2 kg of flour, a shopkeeper had 5/8kg of flour left. How much flour did he have at first?

Answer 1

Let's call the amount of flour the shopkeeper had at first "x" kg.
After selling 14 1/2 kg, the shopkeeper had x - 14 1/2 kg left.
We know that this amount is equal to 5/8 kg.
So we can write the equation: x - 14 1/2 = 5/8.
To add 14 1/2 and 5/8, we need to find a common denominator, which is 8.
14 1/2 is equivalent to 14 4/8. So, the equation becomes: x - 14 4/8 = 5/8.
Now, we can add the fractions: x - 14 4/8 = 5/8.
To do this, we need to find a common denominator, which is 8.
So, x - 118/8 = 5/8.
Next, we can simplify the left side of the equation by subtracting the fractions:
x - 118/8 = 5/8.
Multiplying the denominator and numerator of 118/8 by 8 will give us: x - 118 = 5.
To isolate "x", we need to add 118 to both sides of the equation: x - 118 + 118 = 5 + 118.
This simplifies to: x = 123.
Therefore, the shopkeeper had 123 kg of flour at first.