Asked by Tina
After robbing a bank in Dodge City, a robber gallops off at 13 mi/h. 20 minutes later, the marshall leaves to pursue the robber at 16 mi/h. How long (in hours) does it take the marshall to catch up to the robber?
Answers
Answered by
Reiny
let the time taken by the robber when he is caught be t hrs
distance he covered = 13t miles
time taken by the marshall to catch him = t - 1/3
distance traveled by him = 16(t - 1/3)
but 13t = 16(t - 1/3)
13t = 16t - 16/3
-3t = -16/3
t = 16/9 hrs
time of marshall = t - 1/3
= 16/9 - 1/3 = 13/9 hrs or 1 hour and appr 27 minutes
distance he covered = 13t miles
time taken by the marshall to catch him = t - 1/3
distance traveled by him = 16(t - 1/3)
but 13t = 16(t - 1/3)
13t = 16t - 16/3
-3t = -16/3
t = 16/9 hrs
time of marshall = t - 1/3
= 16/9 - 1/3 = 13/9 hrs or 1 hour and appr 27 minutes
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