calculate his horizontal and vertical velocity components at landing
horizontal (h) ... 24.1 m/s * cos(44.3º)
... this velocity is the same as take off ... no acceleration
vertical (v) ... 24.1 m/s * sin(44.3º)
... this velocity is take off with gravitational acceleration
time of flight (t) is ... (horizontal distance) / (horizontal velocity)
vertical take off velocity is ... v - (g * t)
use the take off velocity components to find the take off velocity
... add the vectors to find the direction and magnitude
After leaving the end of a ski ramp, a ski jumper lands downhill at a point that is displaced 40.5 m horizontally from the end of the ramp. His velocity, just before landing, is 24.1 m/s and points in a direction 44.3° below the horizontal. Neglecting air resistance and any lift he experience, find hid initial velocity ( magnitude and direction) when he left the end of the ramp. Express the direction as an angle relative to the horizontal
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