the velocity of the ball at the ground was
vf^2=2gh
vf=sqrt 2gh.
but this velocity reversed at impact, so the change in velocity is
2sqrt2gh
force*time=2sqrt(2gh)
After falling from rest from a height of 34 m, a 0.47 kg ball rebounds upward, reaching a height of 24 m. If the contact between ball and ground lasted 1.8 ms, what average force was exerted on the ball?
1 answer