To determine the time it takes for the baseball to return to its maximum height, we can use the kinematic equation for vertical motion:
h = u*t - (1/2) * g * t^2
where h is the height, u is the initial velocity (which is zero when the ball reaches maximum height), g is the acceleration due to gravity (approximately -9.8 m/s^2), and t is time.
Given that the maximum height reached by the baseball is 19.6 m, we can write the equation as:
19.6 = 0*t - (1/2) * (-9.8) * t^2
Now, let's solve this equation to find the time it takes for the ball to return to its maximum height:
9.8 * t^2 = 19.6
t^2 = 19.6 / 9.8
t^2 = 2
t = √2 ≈ 1.414 seconds
Therefore, it will take approximately 1.414 seconds for the baseball to return to its maximum height.
after being hit by a bat a baseball flew 19.6m straight up into the air. how long will it take the ball take to return from its maximum height
1 answer