Accgirl=60/hermass
Accsled=150/sledmass
now to get time, 15=1/2 (accgirl+accsled)t^2 solve for t.
Knowing time, vfeach=acc*time
KE= 1/2 masseach*Vfinaleach^2
After an accident, a 60.0 kg Inuit girl finds herself at rest on the frictionless ice of a frozen
lake, 15.0 m north of her stationary 150 kg sled. Fortunately she is connected to the sled
by a rope of negligible mass, so she begins hauling the rope in, maintaining a constant
tension of 50.0 N in it.
Determine:
4.1 the accelerations of the girl and the sled.
4.2 the total kinetic energy of the girl and sled system
(a) just before they meet; and
(b) just after they meet
Hello, I have correctly answered question (4.1) and have determined the accelerations of the girl and sled to be 0.83 m/s^2 South and 0.33 m/s^2 North respectively.
I am having trouble determining question (4.2). I think I should determine the velocities but am not sure
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