it takes her twice as long to go half as far
so she walks a quarter as fast as she rides
w = (d/2) / 2t = 1/4 d/t
r = d/t
after a cyclist has gone 2/3 of her route, she gets a puncture in a tire. Finishing on foot, she spends twice as long walking as she did riding. How many times as fast does she ride as walk?
I know that the answer is 4 but do not know how to get to this answer. Can you please show me the steps?
1 answer
4 answers