After 12.6 s, a spinning roulette wheel has slowed down to an angular velocity of 1.32 rad/s. During this time, the wheel has an angular acceleration of -6.07 rad/s2. Determine the angular displacement of the wheel.

Answer 1

alpha = -6.07
initial omega = wi
final omega = 1.32
t = 12.6

1.322 = wi - 6.07 (12.6) solve for wi
then
theta = wi t - (6.07/2) t^2 = wi(12.6) - (3.035)(12.6)^2