Ade received 3/5 of a sum of money, Nelly 1/3 of the remainder while Austine took the rest. If Austine’s share is greater than Nelly’s share by N3,000.00. How much did Ade received

Answer 1

Let x be the total sum of money.

Ade received 3/5 of x, which is (3/5)x = 3x/5.

The remainder after Ade's share is (5/5 - 3/5)x = 2x/5.

Nelly received 1/3 of the remainder, which is (1/3)(2x/5) = 2x/15.

The rest of the money, which Austine received, is (2x/5) - (2x/15) = 4x/15.

We are given that Austine’s share is greater than Nelly’s share by N3,000.00, so:

4x/15 - 2x/15 = 3000

2x/15 = 3000

2x = 45000

x = 22500

Therefore, Ade received 3/5 of x = 3(22500)/5 = 13500.

Ade received N13,500.