Add the polynomial expressions 2r2−3r+4 and −2r2+3r+6 .

Answer 1

To add the polynomial expressions \(2r^2 - 3r + 4\) and \(-2r^2 + 3r + 6\), you combine like terms:

1. Combine the \(r^2\) terms: \[ 2r^2 + (-2r^2) = 0r^2 \]

2. Combine the \(r\) terms: \[ -3r + 3r = 0r \]

3. Combine the constant terms: \[ 4 + 6 = 10 \]

Now putting it all together, we have: \[ 0r^2 + 0r + 10 = 10 \]

Thus, the sum of the polynomial expressions is: \[ \boxed{10} \]