Add the polynomial expressions 2r²-3r+4 and -2r²+3r+6.

Answer 1

To add the polynomial expressions \( 2r^2 - 3r + 4 \) and \( -2r^2 + 3r + 6 \), you simply combine like terms.

1. Combine \( r^2 \) terms: \[ 2r^2 + (-2r^2) = 0r^2 \]

2. Combine \( r \) terms: \[ -3r + 3r = 0r \]

3. Combine the constant terms: \[ 4 + 6 = 10 \]

Now, putting it all together, you have:

\[ 0r^2 + 0r + 10 = 10 \]

Thus, the result of adding the two polynomial expressions is \( \boxed{10} \).