"Add the ionic equations for part one and three, compare the results with the ionic equation for part two"
Part 1: NaOH(s) = Na+(aq) +OH-(aq) + heat
Part 2: NaOH(s) + H+(aq) +Cl-(aq) = Na+(aq) + Cl-(aq) + H2O(l) + heat
Part 3: Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) = Na+(aq) + Cl-(aq) + H2O(l) + heat
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So I thought if you add part 1 and two, you'd get an equation that looks like this:
NaOH + H + Cl = Na + Cl + H2O + 2 heats?????
Is this what I'm even supposed to do? This is part of an enthalpy lab, if that helps. I'd really, really appreciate help.
I feel like I'm totally wrong and not grasping something somehow.