To combine the terms \(3\sqrt{50} + 5\sqrt{32}\), we first need to simplify the square roots.
-
Simplify \(\sqrt{50}\): \[ \sqrt{50} = \sqrt{25 \cdot 2} = \sqrt{25} \cdot \sqrt{2} = 5\sqrt{2} \] Therefore, \[ 3\sqrt{50} = 3 \cdot 5\sqrt{2} = 15\sqrt{2} \]
-
Simplify \(\sqrt{32}\): \[ \sqrt{32} = \sqrt{16 \cdot 2} = \sqrt{16} \cdot \sqrt{2} = 4\sqrt{2} \] Thus, \[ 5\sqrt{32} = 5 \cdot 4\sqrt{2} = 20\sqrt{2} \]
Now we can combine the terms: \[ 3\sqrt{50} + 5\sqrt{32} = 15\sqrt{2} + 20\sqrt{2} = (15 + 20)\sqrt{2} = 35\sqrt{2} \]
Since we have a single term now, we can choose:
A. \(35\sqrt{2}\)
The answer is:
35\sqrt{2}