To add the monomials \(-3r^2 S\) and \(11r^2 S\), you need to combine the coefficients of the like terms.
\[ -3r^2 S + 11r^2 S = (11 - 3)r^2 S = 8r^2 S \]
So, the sum of the monomials is \(8r^2 S\).
1 answer
To add the monomials \(-3r^2 S\) and \(11r^2 S\), you need to combine the coefficients of the like terms.
\[ -3r^2 S + 11r^2 S = (11 - 3)r^2 S = 8r^2 S \]
So, the sum of the monomials is \(8r^2 S\).