To add the mixed numbers \(1 \frac{4}{5} + 1 \frac{1}{2}\), we first need to convert them into improper fractions.
For \(1 \frac{4}{5}\): \[ 1 \frac{4}{5} = \frac{5 \times 1 + 4}{5} = \frac{5 + 4}{5} = \frac{9}{5} \]
For \(1 \frac{1}{2}\): \[ 1 \frac{1}{2} = \frac{2 \times 1 + 1}{2} = \frac{2 + 1}{2} = \frac{3}{2} \]
Now, we need to add \(\frac{9}{5}\) and \(\frac{3}{2}\). To do this, we need a common denominator. The least common multiple of 5 and 2 is 10.
We convert each fraction: \[ \frac{9}{5} = \frac{9 \times 2}{5 \times 2} = \frac{18}{10} \] \[ \frac{3}{2} = \frac{3 \times 5}{2 \times 5} = \frac{15}{10} \]
Now, we can add the two fractions: \[ \frac{18}{10} + \frac{15}{10} = \frac{18 + 15}{10} = \frac{33}{10} \]
Now we convert \(\frac{33}{10}\) back to a mixed number: \[ 33 \div 10 = 3 \quad \text{(whole number)} \] \[ 33 - (10 \times 3) = 3 \quad \text{(remainder)} \] So, \(\frac{33}{10} = 3 \frac{3}{10}\).
Finally, to answer your question: The whole number is \(3\).
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