Certainly! Here are some practice problems involving the addition and subtraction of radicals, along with their solutions:
Practice Problems:
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Addition: \( \sqrt{18} + \sqrt{2} \)
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Subtraction: \( 3\sqrt{5} - 2\sqrt{5} \)
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Addition: \( 4\sqrt{3} + 5\sqrt{3} \)
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Subtraction: \( \sqrt{32} - \sqrt{18} \)
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Addition: \( \sqrt{50} + \sqrt{8} \)
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Subtraction: \( 6\sqrt{2} - 3\sqrt{8} \)
Solutions:
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Solution to \( \sqrt{18} + \sqrt{2} \):
- Simplify \( \sqrt{18} \) to \( 3\sqrt{2} \) (since \( \sqrt{18} = \sqrt{9 \cdot 2} = 3\sqrt{2} \)).
- Combine: \[ 3\sqrt{2} + \sqrt{2} = 4\sqrt{2} \]
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Solution to \( 3\sqrt{5} - 2\sqrt{5} \):
- Combine like terms: \[ (3 - 2)\sqrt{5} = 1\sqrt{5} = \sqrt{5} \]
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Solution to \( 4\sqrt{3} + 5\sqrt{3} \):
- Combine like terms: \[ (4 + 5)\sqrt{3} = 9\sqrt{3} \]
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Solution to \( \sqrt{32} - \sqrt{18} \):
- Simplify \( \sqrt{32} = 4\sqrt{2} \) and \( \sqrt{18} = 3\sqrt{2} \):
- Combine: \[ 4\sqrt{2} - 3\sqrt{2} = 1\sqrt{2} = \sqrt{2} \]
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Solution to \( \sqrt{50} + \sqrt{8} \):
- Simplify \( \sqrt{50} = 5\sqrt{2} \) and \( \sqrt{8} = 2\sqrt{2} \):
- Combine: \[ 5\sqrt{2} + 2\sqrt{2} = 7\sqrt{2} \]
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Solution to \( 6\sqrt{2} - 3\sqrt{8} \):
- Simplify \( \sqrt{8} = 2\sqrt{2} \):
- Rewrite and combine: \[ 6\sqrt{2} - 3(2\sqrt{2}) = 6\sqrt{2} - 6\sqrt{2} = 0 \]
Summary of Answers:
- \( 4\sqrt{2} \)
- \( \sqrt{5} \)
- \( 9\sqrt{3} \)
- \( \sqrt{2} \)
- \( 7\sqrt{2} \)
- \( 0 \)
Feel free to ask for more practice problems or explanations!