Add −8 1/5+4 1/5.

7 answers

To add the mixed numbers \(-8 \frac{1}{5}\) and \(4 \frac{1}{5}\), we'll first convert them to improper fractions:

  1. Convert \(-8 \frac{1}{5}\): \[ -8 \frac{1}{5} = -\left(8 \times 5 + 1\right)/5 = -\left(40 + 1\right)/5 = -41/5 \]

  2. Convert \(4 \frac{1}{5}\): \[ 4 \frac{1}{5} = (4 \times 5 + 1)/5 = (20 + 1)/5 = 21/5 \]

Now we can perform the addition: \[ -\frac{41}{5} + \frac{21}{5} = \frac{-41 + 21}{5} = \frac{-20}{5} \]

Simplifying \(\frac{-20}{5}\): \[ \frac{-20}{5} = -4 \]

So, the result of adding \(-8 \frac{1}{5}\) and \(4 \frac{1}{5}\) is: \[ -4 \]

can you write that like (fraction)/(fraction)

Certainly! To add \(-8 \frac{1}{5}\) and \(4 \frac{1}{5}\) using a fraction format, we can write it as follows:

  1. Convert to improper fractions:

    • \(-8 \frac{1}{5} = -\frac{41}{5}\)
    • \(4 \frac{1}{5} = \frac{21}{5}\)
  2. Add the fractions: \[ -\frac{41}{5} + \frac{21}{5} = \frac{-41 + 21}{5} = \frac{-20}{5} \]

Therefore, the addition can be written as: \[ \left(-\frac{41}{5} + \frac{21}{5}\right) = \frac{-20}{5} \]

Final result: \[ \frac{-20}{5} = -4 \]

So, in the requested format: \[ \frac{-41}{5} + \frac{21}{5} = \frac{-20}{5} \] And the simplified result is: \[ \frac{-20}{5} = -4 \]

no like, write it like (number)/(number)

Got it! Here’s the addition of \(-8 \frac{1}{5}\) and \(4 \frac{1}{5}\) represented in the form of \((number)/(number)\):

  1. First, convert the mixed numbers to improper fractions:

    • \(-8 \frac{1}{5} = -\frac{41}{5}\)
    • \(4 \frac{1}{5} = \frac{21}{5}\)
  2. Now, write the addition as a single fraction: \[ \frac{-41}{5} + \frac{21}{5} = \frac{-41 + 21}{5} = \frac{-20}{5} \]

So, in the format you requested, the addition looks like this: \[ \frac{-41 + 21}{5} = \frac{-20}{5} \] And the simplified result is: \[ \frac{-20}{5} = -4 \]

Thus, you can see each step laid out in the desired format!

-1\frac{3}{\ 10}+(-4\frac{2}{\ 15})

To add the mixed numbers \(-1 \frac{3}{10}\) and \(-4 \frac{2}{15}\), we will follow these steps:

  1. Convert the mixed numbers to improper fractions:

    \(-1 \frac{3}{10}\): \[ -1 \frac{3}{10} = -\left(1 \times 10 + 3\right)/10 = -\left(10 + 3\right)/10 = -\frac{13}{10} \]

    \(-4 \frac{2}{15}\): \[ -4 \frac{2}{15} = -\left(4 \times 15 + 2\right)/15 = -\left(60 + 2\right)/15 = -\frac{62}{15} \]

  2. Find a common denominator for the improper fractions. The least common multiple (LCM) of 10 and 15 is 30.

  3. Convert each fraction to have the common denominator of 30:

    For \(-\frac{13}{10}\): \[ -\frac{13}{10} = -\frac{13 \times 3}{10 \times 3} = -\frac{39}{30} \]

    For \(-\frac{62}{15}\): \[ -\frac{62}{15} = -\frac{62 \times 2}{15 \times 2} = -\frac{124}{30} \]

  4. Now add the fractions: \[ -\frac{39}{30} + -\frac{124}{30} = \frac{-39 - 124}{30} = \frac{-163}{30} \]

So, the result of adding \(-1 \frac{3}{10}\) and \(-4 \frac{2}{15}\) is: \[ -\frac{163}{30} \]

  1. If needed, you can convert it back to a mixed number: \[ -\frac{163}{30} = -5 \frac{13}{30} \quad (\text{since } 163 \div 30 = 5 \text{ remainder } 13) \]

Thus, the final result is: \[ -\frac{163}{30} \text{ or } -5 \frac{13}{30} \]