Responses
9.1×107
9.1 times 10 superscript 7 baseline
8.1×107
8.1 times 10 superscript 7 baseline
9.1×1014
9.1 times 10 superscript 14 baseline
9.1+107
9 answers
To add \( 7.3 \times 10^7 \) and \( 1.8 \times 10^7 \), you can add the coefficients (the numbers in front) while keeping the exponent the same:
\[ 7.3 + 1.8 = 9.1 \]
So the sum is:
\[ 9.1 \times 10^7 \]
Therefore, the correct response is:
9.1×10^7 (9.1 times 10 superscript 7 baseline)
To find the sum of the populations of the two cities:
The populations are given as:
Before adding, it's often easier to express both numbers in terms of the same power of ten. Let’s convert City B's population to the same exponent as City A:
\[ 1.3 \times 10^5 = 0.13 \times 10^6 \]
\[ 3.45 \times 10^6 + 0.13 \times 10^6 = (3.45 + 0.13) \times 10^6 = 3.58 \times 10^6 \]
Thus, the sum of the populations of the two cities in scientific notation is:
3.58×10^6 (3.58 times 10 superscript 6 baseline)
To find the total weight of the dump truck after adding 15,300 pounds of trash, we can follow these steps:
The weight of the empty dump truck is given as \( 2.8 \times 10^5 \) pounds.
First, we need to express 15,300 pounds in scientific notation.
\[ 15,300 = 1.53 \times 10^4 \]
Now, we will need to add \( 2.8 \times 10^5 \) (the weight of the truck) to \( 1.53 \times 10^4 \) (the weight of the trash). To do this, we should express both numbers in terms of the same power of ten. We can convert \( 1.53 \times 10^4 \) to \( 10^5 \):
\[ 1.53 \times 10^4 = 0.153 \times 10^5 \]
Now we can add the two weights:
\[ 2.8 \times 10^5 + 0.153 \times 10^5 = (2.8 + 0.153) \times 10^5 = 2.953 \times 10^5 \]
The total weight of the dump truck with the added trash in scientific notation is:
2.953×10^5 pounds (2.953 times 10 superscript 5 baseline pounds)
To find the half-life of uranium-238, we start with the half-life of uranium-235 and add the additional time given.
First, we need to convert \( 4.463 \times 10^{11} \) to decimal form:
\[ 4.463 \times 10^{11} = 446,300,000,000 \]
Now, we can compute the half-life of uranium-238:
\[ \text{Half-life of uranium-238} = 700,000,000 + 446,300,000,000 \]
To do the addition:
\[ 700,000,000 + 446,300,000,000 = 447,000,000,000 \]
Thus, the half-life of uranium-238 is:
447,000,000,000 years.
To find the total storage of the mobile phone after adding the additional bytes, we start with the storage capacity of the phone and the additional storage amount:
The storage of the mobile phone is given as \( 1.28 \times 10^{11} \) bytes.
The additional storage is given as \( 384,000,000,000 \) bytes. We can express this in scientific notation:
\[ 384,000,000,000 = 3.84 \times 10^{11} \]
Now, we can add the two capacities:
\[ 1.28 \times 10^{11} + 3.84 \times 10^{11} = (1.28 + 3.84) \times 10^{11} = 5.12 \times 10^{11} \]
Therefore, the total storage of the phone after purchasing the additional bytes is:
5.12×10^11 (5.12 times 10 superscript 11 baseline) bytes.
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