It seems like there might be a typo in the second term of the expression. The plus sign at the end of the second term "( 0.4 - k + )" seems out of place. Assuming the plus sign is a typo and should not be there, let's simplify the expression without it:
Add 5(0.5k - 1) + 2(0.4 - k).
First, distribute the coefficients (5 and 2) across the terms in the parentheses:
5 * 0.5k - 5 * 1 + 2 * 0.4 - 2 * k
Now multiply:
(5 * 0.5)k - (5 * 1) + (2 * 0.4) - (2 * k)
2.5k - 5 + 0.8 - 2k
Combine like terms:
(2.5k - 2k) - 5 + 0.8
0.5k - 5 + 0.8
Now combine the constants:
0.5k - (5 - 0.8)
0.5k - 4.2
So, the simplified expression is:
0.5k - 4.2
Add 5 (0.5 k - 1) + 2 ( 0.4 - k + )
5 answers
Subtract 1/2(z+4)-3(1/4z+1) Use fraction in final form
Subtract \( \frac{1}{2}(z+4) \) - \( 3 \left( \frac{1}{4}z + 1 \right) \):
First, distribute the fractions across the terms in the parentheses:
\[ \frac{1}{2}z + \frac{1}{2} \cdot 4 - 3 \left( \frac{1}{4}z + 1 \right) \]
\[ \frac{1}{2}z + 2 - 3 \cdot \frac{1}{4}z - 3 \cdot 1 \]
Now multiply:
\[ \frac{1}{2}z + 2 - \frac{3}{4}z - 3 \]
Combine like terms:
\[ \left( \frac{1}{2}z - \frac{3}{4}z \right) + (2 - 3) \]
To combine the z terms, convert the first fraction to have a denominator of 4 to match the second fraction:
\[ \left( \frac{2}{4}z - \frac{3}{4}z \right) + (-1) \]
Now combine the fractions:
\[ -\frac{1}{4}z - 1 \]
This is the final expression, with the z term represented as a fraction:
\[ -\frac{1}{4}z - 1 \]
First, distribute the fractions across the terms in the parentheses:
\[ \frac{1}{2}z + \frac{1}{2} \cdot 4 - 3 \left( \frac{1}{4}z + 1 \right) \]
\[ \frac{1}{2}z + 2 - 3 \cdot \frac{1}{4}z - 3 \cdot 1 \]
Now multiply:
\[ \frac{1}{2}z + 2 - \frac{3}{4}z - 3 \]
Combine like terms:
\[ \left( \frac{1}{2}z - \frac{3}{4}z \right) + (2 - 3) \]
To combine the z terms, convert the first fraction to have a denominator of 4 to match the second fraction:
\[ \left( \frac{2}{4}z - \frac{3}{4}z \right) + (-1) \]
Now combine the fractions:
\[ -\frac{1}{4}z - 1 \]
This is the final expression, with the z term represented as a fraction:
\[ -\frac{1}{4}z - 1 \]
English please
Certainly! Let's perform the subtraction step by step in plain English.
We have the expression:
\( \frac{1}{2}(z+4) - 3 \left( \frac{1}{4}z + 1 \right) \)
First, we need to distribute, which means applying the fraction in front of the parentheses to each term inside:
\( \frac{1}{2} \) times z gives us \( \frac{1}{2}z \).
\( \frac{1}{2} \) times 4 gives us \( \frac{1}{2} \times 4 \), which simplifies to 2.
Now we'll do the same thing for the second set of parentheses:
3 times \( \frac{1}{4}z \) gives us \( 3 \times \frac{1}{4}z \). The 3 multiplies with \( \frac{1}{4} \), giving us \( \frac{3}{4}z \).
3 times 1 is simply 3.
Now we have all the parts we need to put together:
\( \frac{1}{2}z + 2 \) and \( -\frac{3}{4}z - 3 \).
Next, we combine like terms, which means grouping the terms with z together and the constant terms together:
\( \frac{1}{2}z - \frac{3}{4}z \) and \( 2 - 3 \).
To subtract the z terms, we need a common denominator, which is 4 in this case:
\( \frac{2}{4}z - \frac{3}{4}z \) gives us \( -\frac{1}{4}z \).
2 minus 3 simply gives us -1.
Now we combine the results:
\( -\frac{1}{4}z - 1 \).
So, our final answer in plain English is:
"Negative one quarter z minus one."
We have the expression:
\( \frac{1}{2}(z+4) - 3 \left( \frac{1}{4}z + 1 \right) \)
First, we need to distribute, which means applying the fraction in front of the parentheses to each term inside:
\( \frac{1}{2} \) times z gives us \( \frac{1}{2}z \).
\( \frac{1}{2} \) times 4 gives us \( \frac{1}{2} \times 4 \), which simplifies to 2.
Now we'll do the same thing for the second set of parentheses:
3 times \( \frac{1}{4}z \) gives us \( 3 \times \frac{1}{4}z \). The 3 multiplies with \( \frac{1}{4} \), giving us \( \frac{3}{4}z \).
3 times 1 is simply 3.
Now we have all the parts we need to put together:
\( \frac{1}{2}z + 2 \) and \( -\frac{3}{4}z - 3 \).
Next, we combine like terms, which means grouping the terms with z together and the constant terms together:
\( \frac{1}{2}z - \frac{3}{4}z \) and \( 2 - 3 \).
To subtract the z terms, we need a common denominator, which is 4 in this case:
\( \frac{2}{4}z - \frac{3}{4}z \) gives us \( -\frac{1}{4}z \).
2 minus 3 simply gives us -1.
Now we combine the results:
\( -\frac{1}{4}z - 1 \).
So, our final answer in plain English is:
"Negative one quarter z minus one."