Add: (4d−3)+(12d+4)

Question

. (1 point)

Answer 1

To add the expressions \( (4d - 3) + (12d + 4) \), we can combine like terms.

1. Combine the \(d\) terms: \[ 4d + 12d = 16d \]

2. Combine the constant terms: \[ -3 + 4 = 1 \]

Putting it all together, we have: \[ (4d - 3) + (12d + 4) = 16d + 1 \]

So, the final answer is: \[ \boxed{16d + 1} \]